(2x+y)(x^2+3xy-2y^2)=

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Solution for (2x+y)(x^2+3xy-2y^2)= equation: 


Simplifying
(2x + y)(x2 + 3xy + -2y2) = 0

Reorder the terms:
(2x + y)(3xy + x2 + -2y2) = 0

Multiply (2x + y) * (3xy + x2 + -2y2)
(2x * (3xy + x2 + -2y2) + y(3xy + x2 + -2y2)) = 0
((3xy * 2x + x2 * 2x + -2y2 * 2x) + y(3xy + x2 + -2y2)) = 0

Reorder the terms:
((-4xy2 + 6x2y + 2x3) + y(3xy + x2 + -2y2)) = 0
((-4xy2 + 6x2y + 2x3) + y(3xy + x2 + -2y2)) = 0
(-4xy2 + 6x2y + 2x3 + (3xy * y + x2 * y + -2y2 * y)) = 0
(-4xy2 + 6x2y + 2x3 + (3xy2 + x2y + -2y3)) = 0

Reorder the terms:
(-4xy2 + 3xy2 + 6x2y + x2y + 2x3 + -2y3) = 0

Combine like terms: -4xy2 + 3xy2 = -1xy2
(-1xy2 + 6x2y + x2y + 2x3 + -2y3) = 0

Combine like terms: 6x2y + x2y = 7x2y
(-1xy2 + 7x2y + 2x3 + -2y3) = 0

Solving
-1xy2 + 7x2y + 2x3 + -2y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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